arduino battery monitor


So I come up with a solution. I made a small capacity tester based on Arduino Nano today I will show you how you can make a capacity tester like this first go through the schematic. I have done this on. Freezing the main circuit is consists of a lithium ion battery load register and a n channel MOSFET Arduino check the battery condition. First. If the battery condition is good, then it will provide 5 volt to the gate of the MOSFET it conducts. That means current will flow from battery positive terminal to the load and MOSFET and finally goes back to the negative terminal. These discharge, the battery over a period of time, already no measure the voltage across the load register. By using these two voltage divider Network, the voltage divider network is connected to analog, pin a 0 and a 1 voltage divided by this resistance. We will get current. That means I is equals to V Y R by using milli function. We can calculate the time also so Q or capacity is equals to current into time. A piece of buzzer is used to give different alert or a world in I to see o le d display is hooked to display different weighted parameters. Now we can move to make the final circuit on a prototype board. Let’S get started.


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Battery charge level – Monitor de batería
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Battery charge level – Monitor de batería


Thermistor Circuit



Originally posted 2016-08-17 00:46:58.

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Comment (29)

  1. Great project! I have tons of 18650 cells and only two imax b6 to test their capacities, i need more capacity testers, can i use arduino pro mini to build this circuit?

    1. Great, brilliant project. Subscribed! I just build one using a 5V Arduino pro mini and a IRF3205 mosfet, and is working flawless. Can you tweak the code to show the discharge time? I have no skills for doing that…

  2. Open Green Energy
    if i leave the circuit discharging and not monitoring, when finishes the display shows Low-V! and i cant see the capacity measured, did i something wrong?

  3. Tel me what IT is in code ” // Vcc = readVcc()/1000.0; // Conevrrt mV to Volt

    // Voltage devider Out = Bat_Volt * R2/(R1+R2 ) // R1 =10K and R2 =10K ”
    10ohm resistor. what is the discharge current

  4. It was mentioned that the current changes over time with the resistor. I think that it might be more accurate if a constant current source connected to the Drain of the Mosfet might improve the accuracy assuming the temperature of the current source can be temperature regulated. Sourcing current that is constant through the resistor will ensure a constant level over time. But may involve intermittent measurements of voltage drop from the current source to keep an accurate reading over time as well as a thermistor to read resistor temperature and cut off the Mosfet temporarily to let the resistor cool down and then continue measurements. I like this project and it is professional. Also was wondering if the code within arduino is being saved or if it is just being sent to the display? Thanks for sharing…

  5. Bat_Volt = 2 * sample1 * Vcc / 1024.0;
    why multiply by two

    8.16v Warning High-V!
    actually measured : 4,085

  6. hiii bro, i cant compile code to arduino nano it says that error compiling for board arduino nano plz help me man i really want your help :)))


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